A coil has resistance and inductance of 10 ohm

Question

and draws a current of 5A when connected across 100V, 50 Hz source Determine the reactive power of the circuit

Answer 1

The reactive power (Q) of a circuit can be calculated using the formula:

Q = VL * IL * sin(φ)

Where:
VL is the voltage across the inductor (V) = IL * XL
IL is the current through the inductor (A) = 5A
XL is the inductive reactance (Ω) = 2πfL
f is the frequency of the source (Hz) = 50 Hz
L is the inductance of the coil (H) = 10Ω

First, let's calculate the inductive reactance:

XL = 2πfL
= 2 * 3.14 * 50 * 10
= 3140 Ω

Next, calculate the voltage across the inductor (VL):

VL = IL * XL
= 5A * 3140 Ω
= 15700 V

Finally, calculate the reactive power of the circuit:

Q = VL * IL * sin(φ)
= 15700 V * 5A * sin(φ)

Since the phase angle (φ) is not provided in the given information, we cannot determine the exact reactive power (Q) of the circuit without additional data.