Asked by Vincent
A coil of inductance 0.04henry and negligible resistance is connected in parallel with a 10ohms resistor, across a 240volts supply of frequency 50hz. Calculate:1) the current through the resistance, 2) the current through the coil, 3)the supply current, 4)the power in the circuit.
Answers
Answered by
bobpursley
I will be happy to critique your thinking.
a) I=V/R=240@0/10=24 amps at 0 phase shift
b) i=V/Z=240@0/Z where z=j2PI*50*.04=4PI@90
i= 240@0/4PI@90=60/PI @ -90
c) supply= a)+b) I would combine them in vector form
d) Power= VdotI=240*IinC *CosThetainC
which will equal 240*24(current in a))
a) I=V/R=240@0/10=24 amps at 0 phase shift
b) i=V/Z=240@0/Z where z=j2PI*50*.04=4PI@90
i= 240@0/4PI@90=60/PI @ -90
c) supply= a)+b) I would combine them in vector form
d) Power= VdotI=240*IinC *CosThetainC
which will equal 240*24(current in a))
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