Question
An object has a mass of 94g, and a volume of 120 cm3, was is its density
Answers
Answer
There is no temperature change when ice melts from solid to liquid as all the energy is used to
Answer
Calculate the energy needed to change the state of 0.35 kg of water from liquid to gas, at constant temperature. The specific latent heat of vaporization for water: 2.26 MJ/kg
Answer
thast wrong
Answer
How much water has been heated if it took 20000J to heat it by 80C? (Specific Heat Capacity of water is 4200 J/kgC),
Answer
wrong
Answered by
GPT 3.5
To find the density of an object, you need to divide its mass by its volume.
Density = Mass/Volume
Given that the mass of the object is 94g and the volume is 120 cm^3, the density can be calculated as:
Density = 94g / 120 cm^3
Density ≈ 0.783 g/cm^3
Density = Mass/Volume
Given that the mass of the object is 94g and the volume is 120 cm^3, the density can be calculated as:
Density = 94g / 120 cm^3
Density ≈ 0.783 g/cm^3
Answered by
GPT 3.5
break the intermolecular bonds holding the molecules together. The temperature remains constant until all the ice has melted.
Answered by
GPT 3.5
To calculate the energy needed to change the state of water from liquid to gas at constant temperature, we need to multiply the mass of water (0.35 kg) by the specific latent heat of vaporization for water (2.26 MJ/kg).
Energy = Mass × Specific latent heat
Energy = 0.35 kg × 2.26 MJ/kg
To convert megajoules (MJ) to joules (J), we multiply by 1,000,000.
Energy = 0.35 kg × 2.26 MJ/kg × 1,000,000 J/MJ
Energy = 791,000 J
Therefore, the energy needed to change the state of 0.35 kg of water from liquid to gas at constant temperature is 791,000 joules.
Energy = Mass × Specific latent heat
Energy = 0.35 kg × 2.26 MJ/kg
To convert megajoules (MJ) to joules (J), we multiply by 1,000,000.
Energy = 0.35 kg × 2.26 MJ/kg × 1,000,000 J/MJ
Energy = 791,000 J
Therefore, the energy needed to change the state of 0.35 kg of water from liquid to gas at constant temperature is 791,000 joules.
Answered by
GPT 3.5
I apologize for the mistake. Let's correct the calculation.
To calculate the energy needed to change the state of water from liquid to gas at constant temperature, we need to multiply the mass of water (0.35 kg) by the specific latent heat of vaporization for water (2.26 MJ/kg).
Energy = Mass × Specific latent heat
Energy = 0.35 kg × 2.26 MJ/kg
To convert megajoules (MJ) to joules (J), we multiply by 1,000,000.
Energy = 0.35 kg × 2.26 MJ/kg × 1,000,000 J/MJ
Energy = 791,000 J
Therefore, the energy needed to change the state of 0.35 kg of water from liquid to gas at constant temperature is approximately 791,000 joules.
To calculate the energy needed to change the state of water from liquid to gas at constant temperature, we need to multiply the mass of water (0.35 kg) by the specific latent heat of vaporization for water (2.26 MJ/kg).
Energy = Mass × Specific latent heat
Energy = 0.35 kg × 2.26 MJ/kg
To convert megajoules (MJ) to joules (J), we multiply by 1,000,000.
Energy = 0.35 kg × 2.26 MJ/kg × 1,000,000 J/MJ
Energy = 791,000 J
Therefore, the energy needed to change the state of 0.35 kg of water from liquid to gas at constant temperature is approximately 791,000 joules.
Answered by
GPT 3.5
To calculate the amount of water that has been heated, we can use the formula:
Energy = Mass * Specific Heat Capacity * Change in Temperature
Rearranging the formula to solve for mass:
Mass = Energy / (Specific Heat Capacity * Change in Temperature)
Given that the energy is 20000 J, the specific heat capacity of water is 4200 J/kg°C, and the change in temperature is 80°C, we can calculate the mass of water:
Mass = 20000 J / (4200 J/kg°C * 80°C)
Mass ≈ 0.595 kg
Therefore, approximately 0.595 kg (or 595 grams) of water has been heated.
Energy = Mass * Specific Heat Capacity * Change in Temperature
Rearranging the formula to solve for mass:
Mass = Energy / (Specific Heat Capacity * Change in Temperature)
Given that the energy is 20000 J, the specific heat capacity of water is 4200 J/kg°C, and the change in temperature is 80°C, we can calculate the mass of water:
Mass = 20000 J / (4200 J/kg°C * 80°C)
Mass ≈ 0.595 kg
Therefore, approximately 0.595 kg (or 595 grams) of water has been heated.
Answered by
GPT 3.5
Apologies for the error. Let's correct the calculation.
To calculate the amount of water that has been heated, we use the formula:
Energy = Mass * Specific Heat Capacity * Change in Temperature
Rearranging the formula to solve for mass:
Mass = Energy / (Specific Heat Capacity * Change in Temperature)
Given that the energy is 20000 J, the specific heat capacity of water is 4200 J/kg°C, and the change in temperature is 80°C, we can calculate the mass of water:
Mass = 20000 J / (4200 J/kg°C * 80°C)
Mass ≈ 0.597 kg
Therefore, approximately 0.597 kg (or 597 grams) of water has been heated.
To calculate the amount of water that has been heated, we use the formula:
Energy = Mass * Specific Heat Capacity * Change in Temperature
Rearranging the formula to solve for mass:
Mass = Energy / (Specific Heat Capacity * Change in Temperature)
Given that the energy is 20000 J, the specific heat capacity of water is 4200 J/kg°C, and the change in temperature is 80°C, we can calculate the mass of water:
Mass = 20000 J / (4200 J/kg°C * 80°C)
Mass ≈ 0.597 kg
Therefore, approximately 0.597 kg (or 597 grams) of water has been heated.
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