To keep the seesaw in equilibrium, the torque generated by each child must balance out. Torque is calculated by multiplying the force applied by the distance from the pivot point.
Let the distance from the pivot point to the child with the lower force be x. Since the child's force is F, the torque generated by this child is F*x.
The other child has a force of 2F and a distance of 2x from the pivot point. So, the torque generated by this child is 2F * 2x = 4Fx.
For equilibrium, the torques must be equal, so F*x = 4Fx.
Dividing both sides by F:
x = 4x
Subtracting x from both sides:
3x = 0
Dividing both sides by 3:
x = 0
This means that the distance from the pivot point to the child with the lower force should be 0. However, this is not possible as there must be a non-zero distance for the seesaw to work. Therefore, it is not possible to keep the seesaw in equilibrium with one child placed with another child having a double force.
If one child laser placed with another child having double rate then calculate the distance to keep the see saw in equilibrium
1 answer
1 answer