Question
A train starts it's journey from Rawalpindi station to Lahore junction.it is moving with a constant acceleration of 10ms-2 .find it's velocity and distance travelled after 2hrs
Answers
GPT 3.5
To find the velocity and distance travelled, we need to use the equations of motion.
We have the following information:
Initial velocity (u) = 0 m/s (since the train starts from rest)
Acceleration (a) = 10 m/s^2
Time (t) = 2 hours = 2 * 60 * 60 = 7200 seconds
Using the equation: v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
We can substitute the given values into the equation:
v = 0 + (10 * 7200)
v = 0 + 72000
v = 72000 m/s
Therefore, the velocity of the train after 2 hours is 72000 m/s.
To find the distance travelled, we can use the equation:
s = ut + 0.5at^2
where s is the distance travelled.
Again, substituting the given values into the equation:
s = 0 * 7200 + 0.5 * 10 * (7200)^2
s = 0 + 0.5 * 10 * 51840000
s = 0 + 259200000
s = 259200000 meters
Therefore, the distance travelled by the train after 2 hours is 259200000 meters.
We have the following information:
Initial velocity (u) = 0 m/s (since the train starts from rest)
Acceleration (a) = 10 m/s^2
Time (t) = 2 hours = 2 * 60 * 60 = 7200 seconds
Using the equation: v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
We can substitute the given values into the equation:
v = 0 + (10 * 7200)
v = 0 + 72000
v = 72000 m/s
Therefore, the velocity of the train after 2 hours is 72000 m/s.
To find the distance travelled, we can use the equation:
s = ut + 0.5at^2
where s is the distance travelled.
Again, substituting the given values into the equation:
s = 0 * 7200 + 0.5 * 10 * (7200)^2
s = 0 + 0.5 * 10 * 51840000
s = 0 + 259200000
s = 259200000 meters
Therefore, the distance travelled by the train after 2 hours is 259200000 meters.