Question

A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of 42 m/s. What is the approximate acceleration of the train during this time?
v^2 = 2as, so
42^2 = 2a*5600
a = 0.1575 m/s^2

Related Questions

A train starts from rest and accelerates uniformly, until it has traveled 3 km and acquired a veloci... A train starts from rest and accelerates uniformly, until it has traveled 3000 m and acquired a velo...