Asked by Docker
A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of 42 m/s. What is the approximate acceleration of the train during this time?
Answers
Answered by
oobleck
v^2 = 2as, so
42^2 = 2a*5600
a = 0.1575 m/s^2
42^2 = 2a*5600
a = 0.1575 m/s^2
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