Asked by jiiiiiiiiii

A train starts from rest and then accelerates at a constant acceleration of 1.4ms-2 for 10s. The train then moves with a constant velocity for a further 20s before the brakes are applied bringing the train to a stop with a constant deacceleration of 2.8ms-2 Calculate the total distance covered by the train.

Please explain and help
Answered by bobpursley
Graph velocity vs time. That area below the graph is the distance covered. You can easily determine the area from basic geometry.
Answered by Henry
V1 = a*t = 1.4 * 10 = 14 m/s.

d1 = V1*t = 14 * 20 = 280 m.

V2^2 = V1^2 + 2a*d2 = 0.
14^2 - 5.6d2 = 0
d2 = 35 m.

d = d1+d2 = 280 + 35 = 315 m. = Total distance.


Answered by NDL
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