Question

find the surface area of a rectangular pyramid with these measurements I=14m, w=10m, and h=15 round your answer to nearest hundredth keep in mind you have the height not the slant height
respones 526.89m 500.0m 531.81m 504.93m

Answer 1

To find the surface area of a rectangular pyramid, we need to calculate the area of each face and then sum them up.

The base of the pyramid is a rectangle with dimensions I = 14m and w = 10m. The area of the base is given by A = I * w.

A = 14m * 10m = 140m^2

Now, let's calculate the area of the four triangular faces. Each face is a right triangle, and we have the height (h = 15m) and one side (I = 14m) of each triangle.

The formula to find the area of a right triangle is A = (1/2) * base * height.

The area of each triangular face can be calculated as follows:

Face 1: A = (1/2) * 14m * 15m = 105m^2
Face 2: A = (1/2) * 14m * 15m = 105m^2
Face 3: A = (1/2) * 10m * 15m = 75m^2
Face 4: A = (1/2) * 10m * 15m = 75m^2

Now we can sum up the areas of all the faces:

Total surface area = 140m^2 + 105m^2 + 105m^2 + 75m^2 + 75m^2 = 500m^2.

Rounding to the nearest hundredth, the surface area of the rectangular pyramid is 500.0m^2.