Question

Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?(1 point)
Responses
9 1/2

2 9/10

3 1/10

3 1/5

Answer 1

simplify it

Answer 2

To find the amount of water remaining in the pot, subtract the amount of water poured out from the original amount of water.

Original amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters

So, the remaining amount of water is:
6 3/10 - 3 1/5 = 6 3/10 - 16/5

To subtract fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 10, so we need to convert 16/5 to have a denominator of 10.

16/5 = (16/5) x (2/2) = 32/10

Now we can subtract the fractions:
6 3/10 - 32/10 = (6 - 32)/10 = -26/10

Since the result is negative, it means that the amount of water poured out is greater than the original amount.

Therefore, the correct answer is: 0 liters.

Answer 3

Apologies for the incorrect calculation earlier. Let's simplify the calculation now.

Original amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters

To subtract fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 10.

So, 6 3/10 - 3 1/5 = (6 x 10 + 3)/10 - (3 x 2 + 1)/10
= (60 + 3)/10 - (6 + 1)/10
= 63/10 - 7/10

Now we can subtract the fractions:
63/10 - 7/10 = (63 - 7)/10 = 56/10

The simplified answer is 5 6/10, which can be further simplified to 5 3/5 or 5.6 liters.