The equation f(x)=32,000(0.92)^x represents the value of the car after x years. Plugging x=3 into the equation, we find:
f(3) = 32,000(0.92)^3
f(3) ≈ 32,000(0.778688)
f(3) ≈ 24,923.40
Therefore, the value of the car after three years is $24,923.40.
Use the table to answer the question x f(x) 0 32,000.00 1 29,440.00 2 27,048.80 3 ? Sydney bought a new car for $32,000.00. If the car depreciates in value by 8% each year, the situation can be modeled by the equation f(x)=32,000(0.92)x . Complete the table to find the value of the car to the nearest cent after three years and write in the same form as the values in the table. (1 point) The value of the car after three years is $
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