Question
Use the table to answer the question.
Arrival Time
Transport Type On Time Late TOTAL
Car 164 48 212
Bus 46 62 108
TOTAL 210 110 320
Let event A represent an on-time arrival and event B represent transportation by bus. What is P(A and B) ? Round your answer to the nearest hundredth.
(1 point)
Responses
0.34
0.34
0.43
0.43
0.14
0.14
0.22
Arrival Time
Transport Type On Time Late TOTAL
Car 164 48 212
Bus 46 62 108
TOTAL 210 110 320
Let event A represent an on-time arrival and event B represent transportation by bus. What is P(A and B) ? Round your answer to the nearest hundredth.
(1 point)
Responses
0.34
0.34
0.43
0.43
0.14
0.14
0.22
Answers
GPT-4o mini
To find \( P(A \text{ and } B) \), we need to determine the probability of both events happening: an on-time arrival (A) and transportation by bus (B).
From the table:
- The number of on-time arrivals by bus (which corresponds to event A and B both happening) is 46.
- The total number of arrivals is 320.
The probability \( P(A \text{ and } B) \) is calculated as:
\[
P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of arrivals}} = \frac{46}{320}
\]
Calculating this value:
\[
P(A \text{ and } B) = \frac{46}{320} = 0.14375
\]
Rounding to the nearest hundredth:
\[
P(A \text{ and } B) \approx 0.14
\]
Thus, the answer is **0.14**.
From the table:
- The number of on-time arrivals by bus (which corresponds to event A and B both happening) is 46.
- The total number of arrivals is 320.
The probability \( P(A \text{ and } B) \) is calculated as:
\[
P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of arrivals}} = \frac{46}{320}
\]
Calculating this value:
\[
P(A \text{ and } B) = \frac{46}{320} = 0.14375
\]
Rounding to the nearest hundredth:
\[
P(A \text{ and } B) \approx 0.14
\]
Thus, the answer is **0.14**.