To find \( P(A \text{ and } B) \), we need to determine the probability of both events happening: an on-time arrival (A) and transportation by bus (B).
From the table:
- The number of on-time arrivals by bus (which corresponds to event A and B both happening) is 46.
- The total number of arrivals is 320.
The probability \( P(A \text{ and } B) \) is calculated as:
\[ P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of arrivals}} = \frac{46}{320} \]
Calculating this value:
\[ P(A \text{ and } B) = \frac{46}{320} = 0.14375 \]
Rounding to the nearest hundredth:
\[ P(A \text{ and } B) \approx 0.14 \]
Thus, the answer is 0.14.