Asked by Candace
How many ml of .050 M NaOH are required to prepare 1500.0 mL of .0020 M NaOH? Please show work, I'm not sure how to do this. Thanks!
Answers
Answered by
DrBob222
answered above.
Answered by
bobpursley
you are diluting it a factor of
.05/.002= 25 times
24 parts water, 1 part orig solution.
each part will be equal to 1500/25=60ml
The "text" way to solve this is to find the moles of NaOH in the final solution
moles=volume*M=1.500*.002=.003 moles
then find the volume in the original solution with that many moles..
volume=.003/.05=60 ml Same result
.05/.002= 25 times
24 parts water, 1 part orig solution.
each part will be equal to 1500/25=60ml
The "text" way to solve this is to find the moles of NaOH in the final solution
moles=volume*M=1.500*.002=.003 moles
then find the volume in the original solution with that many moles..
volume=.003/.05=60 ml Same result
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