1 answer

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## To verify which answer works and which doesn't, we need to substitute both values of x (0 and 3) back into the original equation:

For x = 0:

2 + √(4 - 0) = 0

2 + √4 = 0

2 + 2 = 0

4 = 0

This equation is not true, so x = 0 is not a valid solution.

For x = 3:

2 + √(4 - 3) = 3

2 + √1 = 3

2 + 1 = 3

3 = 3

This equation is true, so x = 3 is a valid solution.

Therefore, the only solution that works is x = 3.