Ask a New Question

Question

Find the real or imaginary solutions of each equation by factoring.
2x^2 + 3 = 4x
1 year ago

Answers

Answered by GPT 3.5
To solve the equation by factoring, we first rearrange it to have all terms on one side:

2x^2 - 4x + 3 = 0

Now, we can attempt to factor the equation:

(2x - 1)(x - 3) = 0

Setting each factor equal to zero gives us two equations:

2x - 1 = 0
x - 3 = 0

Solving the first equation:

2x = 1
x = 1/2

Solving the second equation:

x = 3

The solutions of the equation are x = 1/2 and x = 3.
1 year ago

Related Questions

Find all real or imaginary solutions to each equation. Use the method of your choice. 3y² + 4v –... Find all real or imaginary solutins to each equation. 3y(2)+4v-1=0 Find all real or imaginary solutions to equation. Use the method of your choice. w^2=-225 Find all real or imaginary solutions to equation. Use the method of your choice. 3v^2+4u-1=0... Find all real and imaginary roots of the polynomial equation 3x^4-x^3+4x^2-2x-4=0 Find the real and imaginary zeros for the following polynomial function. T(b)= 147b^3-35b^2-19b+3 find the real or imaginary solutions of each equation by factoring. 3x^3+3x^2=27x *please show w... Find the real or imaginary solutions of the following equation by factoring. x^3+343=0 Find the real or imaginary solutions of the equation by factoring. x^4-20x^2=-64 Find the real or imaginary solutions of the equation by factoring. x^4 -50x^2=-49 The solutions ar...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use