Asked by lexi
find the real or imaginary solutions of each equation by factoring.
3x^3+3x^2=27x
*please show work so i can learn how to do this.
3x^3+3x^2=27x
*please show work so i can learn how to do this.
Answers
Answered by
Steve
first, put into descending powers:
3x^3+3x^2-27x = 0
Now factor out 3x, leaving
3x(x^2+x-9) = 0
so, clearly, x=0 is one solution
use the quadratic formula to find the others. You know they are real, since the discriminant is positive.
3x^3+3x^2-27x = 0
Now factor out 3x, leaving
3x(x^2+x-9) = 0
so, clearly, x=0 is one solution
use the quadratic formula to find the others. You know they are real, since the discriminant is positive.
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