Question
Find the real and imaginary part of 6¡/(2-¡)²
Pls I need working and answer pls
Pls I need working and answer pls
Answers
Steve
where do you get those inverted ! symbols? Use <i>i</i> fer petesake!
6i/(2-i) = 6i/(2-i) * (2+i)/(2+i) = 6i(2+i)/(2^2+1^2) = (-6+12i)/5
6i/(2-i) = 6i/(2-i) * (2+i)/(2+i) = 6i(2+i)/(2^2+1^2) = (-6+12i)/5