Asked by RAYMOND
THE VALUES OF X THAT ARE SOLUTIONS TO THE EQUATION [COSX]^2 = SIN2X IN THE INTERVAL 0 TO PI??
Answers
Reiny
(cosx)^2 = 2sinxcox
(cosx)^2 - 2sinxcosx = 0
cosx(cosx - 2sinx) = 0
cosx = 0 or cosx = 2sinx
if cosx=0 then <b>x = pi/2</b>
if cosx = 2sinx
sinx/cosx = 1/2
tanx = 1/2
<b>x = .46365</b>
(cosx)^2 - 2sinxcosx = 0
cosx(cosx - 2sinx) = 0
cosx = 0 or cosx = 2sinx
if cosx=0 then <b>x = pi/2</b>
if cosx = 2sinx
sinx/cosx = 1/2
tanx = 1/2
<b>x = .46365</b>