Asked by Brea
How many mL of a 6 M HCl solution are required to prepare 200 mL of a 0.2 M solution?
Answers
Answered by
geekgirl95
v1=c2v2/c1
v1= (0.2M)(200ml)/(6M)
v1=6.67 ml HCl
v1= (0.2M)(200ml)/(6M)
v1=6.67 ml HCl
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