x^4-x^3-9+21x-15x^2 divided by x^2+3x-4

Answer 1

In order to perform the division (x^4 - x^3 - 9 + 21x - 15x^2) ÷ (x^2 + 3x - 4), let's first set up the long division:

____________________________________
x^2 + 3x - 4 | x^4 - x^3 - 9 + 21x - 15x^2
-x^4 - 3x^3 + 4x^2
________________________________
2x^3 - 19x^2 + 21x
-2x^3 - 6x^2 + 8x
________________________
-13x^2 + 29x - 9
13x^2 + 39x - 52
___________________
10x + 43

Therefore, the division of (x^4 - x^3 - 9 + 21x - 15x^2) by (x^2 + 3x - 4) is equal to x^2 - 2x + 10, with a remainder of 10x + 43.

Answer 2

i got x^2-4x+1 with a remainder of 2x-13

Answer 3

Apologies for the previous response. Let's divide again:

_______________________
x^2 + 3x - 4 | x^4 - x^3 - 9 + 21x - 15x^2
- (x^4 + 3x^3 - 4x^2)
_______________________
- 4x^3 + 4x^2 + 21x
+ (4x^3 + 12x^2 - 16x)
_______________________
16x^2 + 5x
- (16x^2 + 48x - 64)
____________________
53x - 64
+ (53x + 159)
______________
- 223

Therefore, the correct division of (x^4 - x^3 - 9 + 21x - 15x^2) by (x^2 + 3x - 4) is equal to x^2 - 4x + 1, with a remainder of -223.