Asked by John
6x^3-3x^2+x-40 Divided by x-2
Answers
Answered by
Henry
Use Long-hand division.
(6x^3 - 3x^2 + x - 40)/(x-2)=6x^2+9x+19,
Remainder 2.
(6x^3 - 3x^2 + x - 40)/(x-2)=6x^2+9x+19,
Remainder 2.
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