Asked by Chrissy
                Could someone please explain how to figure this out step by step. I'll give you one of my problems and I'll try to figure out the rest. 
Directions: For each situation find the value of x and the measure of the indicated segment.
1. UY=4x-3, YV=x; UV
            
        Directions: For each situation find the value of x and the measure of the indicated segment.
1. UY=4x-3, YV=x; UV
Answers
                    Answered by
            bobpursley
            
    If UY and YV are segments of a straight line, then
UY+YV=UV
4x-3+x=UV
If one knows UV, then one can solve for x.
    
UY+YV=UV
4x-3+x=UV
If one knows UV, then one can solve for x.
                    Answered by
            Chrissy
            
    Do I add 4x+x which equals 5x so would it be 5x-3=UV??
    
                    Answered by
            Chrissy
            
    could you check the one i did myself
2. UV=x+6,UY=x-1;YV
UY+UY=YV
x+6-1=YV
Answer: x-5=YV
    
2. UV=x+6,UY=x-1;YV
UY+UY=YV
x+6-1=YV
Answer: x-5=YV
                    Answered by
            bobpursley
            
    well, since UV is greater then UY, it means that UV is the longer segment, UY one part of it, and YV the other part.
So UY+YV=UV
then proceed.
    
So UY+YV=UV
then proceed.
                    Answered by
            Chrissy
            
    So would the answer be x^2+YV=7
    
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