Use the properties of operations to add 9(k+13)+10(12k−1).(1 point) Responses 1912k−23 19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction 14k−7 14 k minus 7 14k−23 14 k minus Start Fraction 2 over 3 End Fraction 14k+13

Answer 1

To add 9(k+13)+10(12k−1), we can distribute the numbers inside the parentheses:
9(k+13) expands to 9k + 117
10(12k−1) expands to 120k - 10

Now we can add these two expressions together:
9k + 117 + 120k - 10

Combine like terms by adding the coefficients of the k variables:
(9k + 120k) + (117 - 10) = 129k + 107

So the sum of 9(k+13)+10(12k−1) is 129k + 107.