Asked by Anonymous
How do you solve this equation: 3x-5*√x=2. (√= Is a square root sign)
Answers
Answered by
Cody Libby
is that the original equation? or is it somewhere along the way of one?
Answered by
def
3x-5*√x-2=0
3x-3*√x-2*√x-2=0
3x-3*√x-2*√x-2=0
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