Asked by Linda

For which system is (-2,-3) a solution?

a) 4x+2y=7, x-y=-5

b) 3x=2y, x+y=5

c) x-y=1, 3x-2y=0

d) x-1=2y, 2x-y=-7
Answered by Anonymous
I think it is C.
Answered by MathMate
substitute (-2,-3) into:
c) x-y=1, 3x-2y=0
x-y = -2-(-3) = -2 +3 =1
3x-2y = 3(-2) - 2(-3) = -6 - (-6) = 0
So it <i>is</i> C.
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