Asked by jayla

For the system CaO(s) + CO2(g) = CaCO3(s), I added 1.00 mol of CaO(s) to 1.00L of 0.500M CO2(g) at 200 oC. At equilibrium the [CO2] = 0.150M. What is the value of Kp for this reaction?
Answered by DrBob222
..............CaO + CO2 ==> CaCO3
initial..... 1M...0.5M......
equil..............0.15
0.15M in 1L = 0.15 moles
Use PV = nRT to solve for P, then
Kp = 1/pCO2 = ?
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