To find the average of two numbers, we add them together and divide by 2.
To find the average of 1/3 and 7/8, we add them together:
1/3 + 7/8 = 8/24 + 21/24 = 29/24
So, the average X of 1/3 and 7/8 is 29/24.
Now, to find the average of X and 1/3, we add them together:
29/24 + 1/3 = (29/24)*(3/3) + 8/24 = 87/72 + 24/72 = 111/72
So, the average of X and 1/3 is 111/72.
If X is the average of 1/3 and 7/8, what is the average of x and 1/3
3 answers
huh? the average of a and b is (a+b)/2
x = the average of 1/3 and 7/8 = (1/3 + 7/8)/2 = 29/48
so the average x and 1/3 = (29/48 + 1/3)/2 = 15/32
x = the average of 1/3 and 7/8 = (1/3 + 7/8)/2 = 29/48
so the average x and 1/3 = (29/48 + 1/3)/2 = 15/32
Apologies for the confusion. You are correct. The average of two numbers is indeed the sum of the numbers divided by 2.
To find the average of 1/3 and 7/8:
X = (1/3 + 7/8)/2
To simplify the expression inside the parentheses, we need to find a common denominator:
X = (8/24 + 21/24)/2 = 29/24
So, the average X of 1/3 and 7/8 is 29/24.
Now, to find the average of X and 1/3:
Average = (29/24 + 1/3)/2
Finding a common denominator:
Average = (29/24 + 8/24)/2 = 37/24
So, the average of X and 1/3 is 37/24.
To find the average of 1/3 and 7/8:
X = (1/3 + 7/8)/2
To simplify the expression inside the parentheses, we need to find a common denominator:
X = (8/24 + 21/24)/2 = 29/24
So, the average X of 1/3 and 7/8 is 29/24.
Now, to find the average of X and 1/3:
Average = (29/24 + 1/3)/2
Finding a common denominator:
Average = (29/24 + 8/24)/2 = 37/24
So, the average of X and 1/3 is 37/24.