Asked by Taylor
Using your average value for Kc (6.92x10^2) and the concentrations provided for the reactants (0.00111mol/L for both), determine the absorbance expected when a 16.00mL of Fe3+ is reacted with 10.00ml of SCN and measured in a 1.00cm cuvette.
Answers
Answered by
DrBob222
M Fe^3+ = 1.11E-3 x (16/26) = ? and lets calls this a.
M SCN^- = 1.11E-3 x (10/26) = ? and let's call this b.
......Fe^3+ + CN^- --> FeCNS^2+
I.....a........b.........0
C....-x.......-x.........x
E....a-x.......b-x.......x
Substitute the E line into the Kc expression and solve for x, then evaluate the final concentrations. You cannot predict an absorbance for the final solution unless you know the absorptivity (molar or otherwise) OR unless you have an absorbance value for some known concentration.
M SCN^- = 1.11E-3 x (10/26) = ? and let's call this b.
......Fe^3+ + CN^- --> FeCNS^2+
I.....a........b.........0
C....-x.......-x.........x
E....a-x.......b-x.......x
Substitute the E line into the Kc expression and solve for x, then evaluate the final concentrations. You cannot predict an absorbance for the final solution unless you know the absorptivity (molar or otherwise) OR unless you have an absorbance value for some known concentration.
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