d perimeter of d isoscelence triangle 7.2 is 28 dy draw isoscelence triangle A
4y cm (6y-2x+1)cm
(x+2y)cm
find x and y and hence state the lengths of d sides of d triangle.
The triangle is isosceles if AB = BC, or BC = AC, or AB = AC. Without that information on side lengths, I can't tell you if it is or not.
B(1,5),c(5,3),and a(1,1)
Do you know how I can find x if AB = 4x and BC = 2x + 10.
As drwls pointed out, using these 3 points you have to find the lengths of AB, BC, and AC.
if two of them are equal you have an isosceles triangle, if all three are equal the triangle is equilateral
Use your "distance between two points" formula
is AB equal to BC???
if so, then set 4x=2x+10 and solve. Easy!!
otherwise the question makes no sense
4y cm (6y-2x+1)cm
(x+2y)cm
find x and y and hence state the lengths of d sides of d triangle.
distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Let's use this formula to find the lengths of the sides AB, BC, and AC.
AB:
Given points B(1, 5) and A(1, 1)
Using the distance formula:
AB = sqrt((1 - 1)^2 + (5 - 1)^2) = sqrt(16) = 4
BC:
Given points B(1, 5) and C(5, 3)
Using the distance formula:
BC = sqrt((5 - 1)^2 + (3 - 5)^2) = sqrt(16 + 4) = sqrt(20) = 2√5
AC:
Given points A(1, 1) and C(5, 3)
Using the distance formula:
AC = sqrt((5 - 1)^2 + (3 - 1)^2) = sqrt(16 + 4) = sqrt(20) = 2√5
Now, to determine if the triangle is isosceles, we compare the lengths of the sides:
AB = 4
BC = 2√5
AC = 2√5
Since AB is not equal to BC or AC, and BC is not equal to AC, the triangle is not an isosceles triangle.
Regarding your second question, if you are given that AB = 4x and BC = 2x + 10, you can solve for x by setting the two expressions equal to each other:
4x = 2x + 10
Simplifying the equation:
2x = 10
Dividing both sides by 2:
x = 5
So, if AB = 4x and BC = 2x + 10, when x = 5, AB would be 20 and BC would be 20.