Asked by Katie

Please help me, thank you.

A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?
Answered by connie (lost)
multiply (simplified fraction)

-8/3*(7/1)

Answered by Katie
that's not right can someone please help.
Answered by MathMate
I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.
M<sub>1</sub>V<sub>1</sub> + M<sub>2</sub>V<sub>2</sub> = 0
100*8 + 45000*V<sub>2</sub> = 0
V<sub>2</sub>
= -100*8/45000
= -0.0178 m/s.
Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut.
Answered by MathMate
Erratum:
Answer: The spaceship moves at 0.0178 <b>m/s</b> in the opposite direction as the astronaut.
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