Asked by Tj
a proton moves in a circle in a uniform magnetic field of 1T, pointing into the page. Its speed is 1.5 x 10 ^5 m/s. What is the radius of its path?
Answers
Answered by
Count Iblis
B q v = m v^2/r -------->
r = m v/(B q)
r = m v/(B q)
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