Question
A 905 kg car moves in a circle of radius 13.1 meters in a flat parking lot. If the car can travel at 9.1 m/s without slipping, what is the force of friction between each tire and the parking lot? What is the coefficient of friction between each tire and the lot? (Remember that there are four tires on a car)
Answers
Damon
do it for 1/4 of mass on one tire
F = m v^2/r = mu m g
where m = 905/4
F = m v^2/r = mu m g
where m = 905/4