The point-slope form of a linear equation is given by:
y - y₁ = m(x - x₁)
where (x₁, y₁) represents a point on the line, and m is the slope.
Using the given point (-13,15) and slope 11, we can substitute these values into the point-slope form:
y - 15 = 11(x - (-13))
Simplifying:
y - 15 = 11(x + 13)
Expanding the parentheses:
y - 15 = 11x + 143
Adding 15 to both sides of the equation:
y = 11x + 158
Therefore, the equation of the line in point-slope form is y = 11x + 158.
Use point-slope form to write the equation of a line that passes through the point left bracket, minus, 13, comma, 15, right bracket(−13,15) with slope 11.
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