If the left is less than zero, then either the first parenthesis is negative, or the second, but not both.
I will do one for you, the first paren negative, second positive.
x>5 for second +, x<-3 for the first negative or -3>x>5.
You do the second condition
Please solve:
(x+3)(x-5) < 0
2 answers
Do we use the FOIL method here? This is what I got..
(x+3) (x-5) < 0
(x+3<0 and x-5>0) or (x+3>0 and x-5<0)
(x<-3 and x>5) or (x>-3and x<5)
(x<-3 and x>5) or (-3 < x < 5)
-3 < x < 5
Is any of this correct?
(x+3) (x-5) < 0
(x+3<0 and x-5>0) or (x+3>0 and x-5<0)
(x<-3 and x>5) or (x>-3and x<5)
(x<-3 and x>5) or (-3 < x < 5)
-3 < x < 5
Is any of this correct?
1 answer