Question

divide 9√33 and 27√11

Answer 1

wrong

Answer 2

To divide √33 and √11, we can use the property of radicals that states √(a) / √(b) = √(a/b).

First, √33 / √11 can be simplified to √(33/11). Simplifying further, we have:

√(33/11) = √3

Therefore, √33 / √11 = √3.

Now, let's divide 9√33 by 27√11:

(9√33) / (27√11)

Using the property mentioned earlier, we can rewrite the expression as:

(9/27) * (√33 / √11)

Now, simplify the fraction:

(9/27) = 1/3

Therefore, the expression simplifies to:

(1/3) * √3

Multiplying 1/3 and √3, we finally get:

√3/3

So, 9√33 divided by 27√11 equals √3/3.

Answer 3

Apologies for the mistake in my previous response. Let's correct it.

To divide 9√33 by 27√11, we can simplify it using the property of radicals that states √(a) / √(b) = √(a/b).

First, divide the numbers outside the radicals: 9/27 = 1/3.

Next, divide the numbers inside the radicals: √33 / √11 = √(33/11) = √3.

Putting it all together, we have:

(9√33) / (27√11) = (1/3) * √3

Therefore, 9√33 divided by 27√11 simplifies to (1/3) * √3.