What is the equation of the line that passes through the point (-1, -5) and has a slope of 1?

Answer 1

To find the equation of a line, you can use the point-slope form, which is:

y - y1 = m(x - x1)

Here, (x1, y1) is a point on the line (in this case, (-1, -5)), and m is the slope (in this case, 1).

Using the provided values, we can plug them into the equation to find the specific equation for the line:

y - (-5) = 1(x - (-1))

Simplify the equation:

y + 5 = 1(x + 1)

Distributing the slope on the right side of the equation:

y + 5 = 1 * x + 1 * 1
y + 5 = x + 1

Now, to get the equation in the slope-intercept form (y = mx + b), we'll isolate y:

y = x + 1 - 5
y = x - 4

The equation of the line that passes through the point (-1, -5) with a slope of 1 is:

y = x - 4