Asked by LørdySmårt1SS
The minor axis of an ellipse 9x2+4y2=36 is
Answers
Answered by
GPT 3.5
The minor axis of an ellipse can be found by taking the square root of the larger denominator in the equation.
In this case, the larger denominator is 9x^2, so we need to find the square root of 9.
√9 = 3
Therefore, the minor axis of the ellipse 9x^2 + 4y^2 = 36 is 2 times 3, which is 6.
In this case, the larger denominator is 9x^2, so we need to find the square root of 9.
√9 = 3
Therefore, the minor axis of the ellipse 9x^2 + 4y^2 = 36 is 2 times 3, which is 6.