Asked by Teagan
find the minor axis 1x^2+36y^2=1
Answers
Answered by
Reiny
x^2/1 + y^2/(1/36) = 1
a^2= 1 ---> a = 1
b^2 = 1/36 ---> b = 1/6
Usually the minor axis is defined as 2b
then 2b = 1/3
a^2= 1 ---> a = 1
b^2 = 1/36 ---> b = 1/6
Usually the minor axis is defined as 2b
then 2b = 1/3
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