Question

An 80N-force extends a spring of natural length 8m by 0.4m what will be the length of the spring when the applied force is 100N?

Answer 1

To solve this problem, we can use Hooke's Law, which states that the force applied to a spring is directly proportional to the extension or compression of the spring. Mathematically, we can represent this as F = kx, where F is the force applied, k is the spring constant, and x is the extension or compression of the spring.

We have been given that a force of 80N extends the spring by 0.4m. We can use this information to find the spring constant (k):

80N = k * 0.4m
k = 80N / 0.4m
k = 200 N/m

Now we can use the spring constant to find the length of the spring when a force of 100N is applied. Let's assume the new length of the spring is L:

100N = 200 N/m * (L - 8m)
100N = 200 N/m * L - 1600 N/m
200 N/m * L = 100N + 1600 N/m
200 N/m * L = 1700 N/m
L = 1700 N/m / 200 N/m
L = 8.5m

Therefore, when a force of 100N is applied, the length of the spring will be 8.5m.