Question
A spiral spring extends from a lend of 10.00cm to 10.01cm when a force of 20N is applied on Newton calculate the force constant of the spring?
Answers
Anonymous
Force = constant * extension distance
If you really mean delta x = 0.01 centimeters
(and not 0.01 meters)
then
20 newtons = k * 0.0001 meters
k = 20 / 0.0001 = 200000/1 = 200,000 Newtons/meter
If you really mean delta x = 0.01 centimeters
(and not 0.01 meters)
then
20 newtons = k * 0.0001 meters
k = 20 / 0.0001 = 200000/1 = 200,000 Newtons/meter