Asked by Chidiebele
A spiral spring extends from a lend of 10.00cm to 10.01cm when a force of 20N is applied on Newton calculate the force constant of the spring?
Answers
Answered by
Anonymous
Force = constant * extension distance
If you really mean delta x = 0.01 centimeters
(and not 0.01 meters)
then
20 newtons = k * 0.0001 meters
k = 20 / 0.0001 = 200000/1 = 200,000 Newtons/meter
If you really mean delta x = 0.01 centimeters
(and not 0.01 meters)
then
20 newtons = k * 0.0001 meters
k = 20 / 0.0001 = 200000/1 = 200,000 Newtons/meter
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.