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A PVC pipe that is one meter long is struck and the speed of sound is 345 m/s. What is the fundamental frequency (n=1) of the p...Asked by Sarah
A PVC pipe that is one meter long is struck and the speed of sound is 345 m/s. What is the fundamental frequency (n=1) of the pipe when:
a.The pipe is open at both ends?
b.The pipe is closed at one end, open at the other?
a.The pipe is open at both ends?
b.The pipe is closed at one end, open at the other?
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Answered by
MathMate
The phenomenon is called a standing longitudinal wave, or a stationary wave.
The part of the tude Where air does not vibrate is called a node.
In the case of an open tube, the node is at mid-length of the pipe, and the open ends have maximum amplitude. So the length of the tude is half the wave-length of 2 m. The frequency is therefore 345/2=172.5 Hz.
For the tude closed at one end, the node is at the closed end, and maximum amplitude at the open end. The length of the tude is 1/4 of the wavelength of 4 m. The frequency is 345/4=86 Hz.
The following link gives a visual description of the above:
(Broken Link Removed)
The part of the tude Where air does not vibrate is called a node.
In the case of an open tube, the node is at mid-length of the pipe, and the open ends have maximum amplitude. So the length of the tude is half the wave-length of 2 m. The frequency is therefore 345/2=172.5 Hz.
For the tude closed at one end, the node is at the closed end, and maximum amplitude at the open end. The length of the tude is 1/4 of the wavelength of 4 m. The frequency is 345/4=86 Hz.
The following link gives a visual description of the above:
(Broken Link Removed)
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