let x = the side of the 1st square
let 2x/3-10 = the side of the 2nd square ("10 less than 2/3 of the side of the other square")
The area of a square is x^2. Therefore, if the sum of the areas = 1000, than
x^2 + (2x/3-10)^2 = 1000
foil the polynomial:
x^2 + (4x^2/9 - 40x/3 + 100) = 1000
You can simplify it and use the quadriatic equation to solve. The numbers do not seem very friendly though - is this a calculator problem? (If so, just use the graphing function to find solutions.)
Babylonian Problem - circa 1800 BC
An area, A, consisting of the sum of two squares is 1000. The side of one square is 10 less than 2/3 of the side of the other square. What are the sides of the squares?
3 answers
Side of square 1 is 30
Side of square 2 is 10
Side of square 2 is 10
peter is twice a old as paul was when peter was asold as paul now. the combined ages of peter and paul is 56 years. how old are peter and paul now?
1 answer