To find the zeroes of the equation y = x^2 - 2x - 15, we need to solve the equation when y is equal to zero.
0 = x^2 - 2x - 15
This equation can be factored as:
0 = (x - 5)(x + 3)
Setting each factor to zero, we have:
x - 5 = 0 or x + 3 = 0
Solving these equations:
x = 5 or x = -3
Therefore, the zeroes of the equation are x = 5 and x = -3.
What are the zeroes of y=x2−2x−15%0D%0A%0D%0A=%0D%0A%0D%0A2%0D%0A−%0D%0A2%0D%0A%0D%0A−%0D%0A15%0D%0A?
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