Question
Evaluate the definite integral
The S thingy has 1 at the bottom and 9 at the top. 4x^2+5 divided by the sqrt of x.
The S thingy has 1 at the bottom and 9 at the top. 4x^2+5 divided by the sqrt of x.
Answers
MathMate
The S thingy is called the integral sign.
The number at the bottom (1) is the lower limit of a definite integral, and the top number (9) is the upper limit of integration.
The expression to be evaluated probably looks similar to this:
I = ∫<sub>1</sub><sup>9</sup> (4*x^2+5)/sqrt(x) dx
If you use the substitution
u=sqrt(x), then
du=(1/2)*dx/sqrt(x)
Substituting the limits and the variables involving x, we get
I= ∫<sub>1</sub><sup>9</sup> (4*x^2+5)/sqrt(x) dx
= ∫<sub>sqrt(x)</sub><sup>sqrt(9)</sup> (4u^4+5)*2 du
= ∫<sub>sqrt(x)</sub><sup>sqrt(9)</sup> (4u^4+5)*2 du
Continuing the integration and evaluate the integral according to the integration limits, we should obtain 2036/5 as the numerical answer.
Post if you need more details.
The number at the bottom (1) is the lower limit of a definite integral, and the top number (9) is the upper limit of integration.
The expression to be evaluated probably looks similar to this:
I = ∫<sub>1</sub><sup>9</sup> (4*x^2+5)/sqrt(x) dx
If you use the substitution
u=sqrt(x), then
du=(1/2)*dx/sqrt(x)
Substituting the limits and the variables involving x, we get
I= ∫<sub>1</sub><sup>9</sup> (4*x^2+5)/sqrt(x) dx
= ∫<sub>sqrt(x)</sub><sup>sqrt(9)</sup> (4u^4+5)*2 du
= ∫<sub>sqrt(x)</sub><sup>sqrt(9)</sup> (4u^4+5)*2 du
Continuing the integration and evaluate the integral according to the integration limits, we should obtain 2036/5 as the numerical answer.
Post if you need more details.
Z32
Thanks for the help!
MathMate
In case it confused you, the substituted lower limit should have read sqrt(1).