Asked by B.B.
                The question is this: You know that a number is divisible by 6 if it is divisible by both 3 and 2. So why isn't a number divisible by 8 if it is divisible by both 4 and 2? My answer is this: The only prime factors of 6 are 2 and 3. So, if a number is divisible by both, then it is divisible by their product,6. The prime factors of 8 are 2, 3 times. In order for a number to be divisible by 8 it must have 3 factors of 2. If a number is divisible by 2 the quotient of that divisible by 4 , then the original number is divisible by 8. Is this right?
            
            
        Answers
                    Answered by
            bobpursley
            
    correct, but wordy.
    
                    Answered by
            Naviana
            
    Six
    
                    Answered by
            hi
            
    this is bullying me
    
                    Answered by
            hi
            
    no
    
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