Asked by B.B.
The question is this: You know that a number is divisible by 6 if it is divisible by both 3 and 2. So why isn't a number divisible by 8 if it is divisible by both 4 and 2? My answer is this: The only prime factors of 6 are 2 and 3. So, if a number is divisible by both, then it is divisible by their product,6. The prime factors of 8 are 2, 3 times. In order for a number to be divisible by 8 it must have 3 factors of 2. If a number is divisible by 2 the quotient of that divisible by 4 , then the original number is divisible by 8. Is this right?
Answers
Answered by
bobpursley
correct, but wordy.
Answered by
Naviana
Six
Answered by
hi
this is bullying me
Answered by
hi
no