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In a CH3CF2CHF2 molecule, which conformation is more stable and how much more is one stable than the other?

I think Anti is more stable than gauche. I don't know why, I just think that a molecule is most stable in it's anti form.

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The anti would be more stable for CH3CH2CH3. However, the replacement of 3 H's by F's changes that. The gauche (eclipsed) position would be favored in CH3CF2CHF2 because of the formation of hydrogen bonding between the H's and the F's.
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