Asked by Lucy
Given that y=x^2+2x-3
When x is -3 what is y?
Is the ans 0?
When x is 1 what is y?
Is the ans 0?
When x is -3 what is y?
Is the ans 0?
When x is 1 what is y?
Is the ans 0?
Answers
Answered by
Sally
if x=-3, then y=-3, not zero:
y=-3^2-6-3
y=6-6-3
y=-3
Does this make sense?
if x=1, then y=0, you are correct:
y=1^2+2-3
y=1+2-3
y=3-3
y=0
Does this make sense?
Hope this helps!! :-)
y=-3^2-6-3
y=6-6-3
y=-3
Does this make sense?
if x=1, then y=0, you are correct:
y=1^2+2-3
y=1+2-3
y=3-3
y=0
Does this make sense?
Hope this helps!! :-)
Answered by
PsyDAG
Sally has made a mistake. (-3)^2 = 9 not 6.
y=-3^2-6-3 = 9 - 6 - 3 = 0
The second value solution is correct.
I hope this helps a little more. Thanks for asking.
y=-3^2-6-3 = 9 - 6 - 3 = 0
The second value solution is correct.
I hope this helps a little more. Thanks for asking.
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