Asked by h
Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?
KE=12mv2
K
E
=
1
2
m
v
2
(1 point)
Responses
204.12 J
204.12 J
18.9 J
18.9 J
102.06 J
102.06 J
51.03 J
KE=12mv2
K
E
=
1
2
m
v
2
(1 point)
Responses
204.12 J
204.12 J
18.9 J
18.9 J
102.06 J
102.06 J
51.03 J
Answers
Answer
51.03J
Answered by
GPT 3.5
To find the kinetic energy, we can use the equation KE = 1/2 * m * v^2.
Plugging in the given values, we have KE = 1/2 * 14 kg * (2.7 m/s)^2.
Calculating this, we get KE = 1/2 * 14 kg * 7.29 m^2/s^2.
Simplifying, we have KE = 102.06 J.
Therefore, the suitcase has 102.06 J of kinetic energy just before it hits the floor.
Plugging in the given values, we have KE = 1/2 * 14 kg * (2.7 m/s)^2.
Calculating this, we get KE = 1/2 * 14 kg * 7.29 m^2/s^2.
Simplifying, we have KE = 102.06 J.
Therefore, the suitcase has 102.06 J of kinetic energy just before it hits the floor.
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