Asked by John
A 320 N bench is 2.40m long. The legs are .30m from each end and weigh 15.0 N each. If 3 persons weighing in order ,500 N, 750N, and 1000N sit .40m, 1.20m, and 2m respectively from one end of the bench, what downward force must each set of legs exert on the floor?
Answers
Answered by
Damon
weight = 320+ 4*15 + 500 + 750 + 1000 = total force up
moments around one end
Ff=force up from floor at far end
Fn = force up at near end
320(1.2)-Fn*.3+30*.3+500*.4+750*1.2
+1000*2 +30*2.1-Ff*2.1 = 0
but Fn = (total force up - Ff)
moments around one end
Ff=force up from floor at far end
Fn = force up at near end
320(1.2)-Fn*.3+30*.3+500*.4+750*1.2
+1000*2 +30*2.1-Ff*2.1 = 0
but Fn = (total force up - Ff)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.