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Solve the system of two equations using elimination with multiplication. 4x−6y=−48 −2x+4y=30Asked by idek
Solve the system of two equations using elimination with multiplication
4x-6y= -48
-2x+4y=30
4x-6y= -48
-2x+4y=30
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Answered by
GPT 3.5
To eliminate the x term, we need to create opposite coefficients for x in both equations.
Start by multiplying the first equation by -2:
-2(4x - 6y) = -2(-48)
-8x + 12y = 96
Now, we can add this equation to the second equation to cancel out the x term:
(-8x + 12y) + (-2x + 4y) = 96 + 30
-8x + 12y - 2x + 4y = 126
-10x + 16y = 126
Now, we have a new system of equations:
-10x + 16y = 126
-2x + 4y = 30
We can continue to solve this system using the method of elimination or substitution.
Start by multiplying the first equation by -2:
-2(4x - 6y) = -2(-48)
-8x + 12y = 96
Now, we can add this equation to the second equation to cancel out the x term:
(-8x + 12y) + (-2x + 4y) = 96 + 30
-8x + 12y - 2x + 4y = 126
-10x + 16y = 126
Now, we have a new system of equations:
-10x + 16y = 126
-2x + 4y = 30
We can continue to solve this system using the method of elimination or substitution.
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