Asked by STACEY
Factorise copletely
1) 2ax+3ay-2bx-3by
2)5x^2-20
3)3x^2+4x-15 is the ans to this one = 7x^3-15
1) 2ax+3ay-2bx-3by
2)5x^2-20
3)3x^2+4x-15 is the ans to this one = 7x^3-15
Answers
Answered by
Damon
You mean factor
a(2x+3y)-b(2x+3y)
= (a-b)(2x+3y)
5(x^2-4)
= 5 (x-2)(x+2)
(3x-5)(x+3)
a(2x+3y)-b(2x+3y)
= (a-b)(2x+3y)
5(x^2-4)
= 5 (x-2)(x+2)
(3x-5)(x+3)
Answered by
Reiny
first one is "grouping"
2ax+3ay-2bx-3by
= a(2x+3y) - b(2x+3y)
= (2x+3y)(a-b)
second, common factor then difference of squares
5x^2-20
= 5(x^2 - 4)
= 5(x+2)(x-2)
third, general quadratic
3x^2+4x-15
= (3x-5)(x+3)
looks like you got your answer by
adding 3x^2 + 4x to get 7x^3
that is just unforgivable!
2ax+3ay-2bx-3by
= a(2x+3y) - b(2x+3y)
= (2x+3y)(a-b)
second, common factor then difference of squares
5x^2-20
= 5(x^2 - 4)
= 5(x+2)(x-2)
third, general quadratic
3x^2+4x-15
= (3x-5)(x+3)
looks like you got your answer by
adding 3x^2 + 4x to get 7x^3
that is just unforgivable!
Answer
2ax+3ay-2bx-3by factorize